if area of isosceles right triangle is 8cm^2. find the perimeter
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Answer:
Step-by-step explanation:
We have a right triangle whose area is 8 cm²
Well, in right isosceles ∆ base and height are equal. Let each of them be x
8 cm² = 1/2 × x × x
16 cm² = x² or x = √16 cm² or 4 cm
Now, h² = b² + p²
h² = 4² + 4²
h = √32 cm² or 4√2 cm
Now, perimeter of isosceles ∆
= 4 cm + 4 cm + 4√2 cm
= 8 + 4√2 cm
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