Question

If area of metal plate of capacitor with capacitance C is doubled then capacitance C will become…
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Answer 1

Given:

Area of metal plate of capacitor with capacitance C is doubled.

To find:

New capacitance?

Calculation:

Let's assume that the capacitor is a PARALLEL PLATE CAPACITOR, with area 'A' and separation of plate 'd'.

So, initial capacitance:

$C = \dfrac{ \epsilon_{0}A}{d}$

Now, area is doubled keeping the other parameters same:

$C_{2}= \dfrac{ \epsilon_{0}(2A)}{d}$

$\implies C_{2}= 2 \times \dfrac{ \epsilon_{0}A}{d}$

$\implies C_{2}= 2 C$

So, capacitance is doubled.