Question

if area of piston A is 0.05 m^2 and that of B is 0.15 m^2. what fore is produced in piston B when 20 N force is applied in piston A​

Answer 1

Answer:

F1/A1 = F2/A2

Explanation:

20/0.05 = F2/0.15

2000/5 = F2/0.15

400 x 0.15 = F2

F2 = 4 x 15= 60 N