Question

If area of quadrant of a circle is 38.5 cm? then find its diameter
(useπ 22/7​

Answer 1

Given :-

Area of quadrant = 38.5cm^2

=> theta/360° * pi * r^2

We know that the angle of a quadrant is 90°

=> 90°/360° * 22/7 * r^2 = 38.5cm^2

=> 4 * 22/7 * r^2 = 38.5cm^2

=> r^2 = 38.5 * 7/88

=> r = underroot(269.5/88)

=> r = 1.75cm

Diameter = 2r = 2 * 1.75 = 3.5cm

Answer 2

Answer:

The diameter of quadrant of a circle is 14 cm.

Step-by-step explanation:

The Accurate Question :

If area of quadrant of a circle is 38.5 cm², then find its diameter.

Solution :

Given :

Shape - Quadrant Circle.

Area - 38.5 cm.

To Find :

The Diameter.

Method :

We know that :

Area of a circle :

$\bigstar\;\boxed{\bf A=\pi r^2}}$

But, it is given that there are four quadrants.

So,

$\bigstar\;\boxed{\bf A_q=\frac{1}{4}\times \pi r^2}$

Now,

$\sf\\ \\\implies 38.5=\frac{1}{4}\times \dfrac{22}{7}\times r^2\\ \\\implies 38.5=\dfrac{11}{14}\times r^2\\ \\\implies r^2=\dfrac{38.5\cdot14}{11}\\ \\\implies r^2=49\\ \\\implies r=7$

We know,

The diameter of the circle is twice the radius.

That's why,

⇒ d = 2r

⇒ d = 2 × 7

⇒ d = 14 cm.

∴ The diameter of quadrant of a circle is 14 cm.

$\rule{300}{1.5}$

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