Question

If area of qudarant of a circle is 38.5cm^. Then find its diameter (use 22/7)

Answer 1

Step-by-step explanation:

Area of quadrant =

$\frac{1}{4} \pi {r}^{2} \\ 38.5= \frac{1}{4} \times \frac{22}{7} \times {r}^{2} \\ {r}^{2} = 38.5 \times 4 \times \frac{7}{22} \\ {r}^{2} = \frac{1078}{22} \\ {r}^{2} = 49 \\ r \: = 7 \\ therefore \: diameter \: = \: 14cm$

Answer 2

Diameter of the circle is 14 cm.

Step-by-step explanation:

It has been given that area of quadrant of a circle is 38.5 cm².

Area of a circle is given by

$A=\pi r^2$

Now, there are four quadrants, So, area of a quadrant is one fourth of the area of circle.

$A_q=\frac{1}{4}\cdot\pi r^2$

Substituting the values and find r

$38.5=\frac{1}{4}\cdot\frac{22}{7}\cdot r^2\\\\38.5=\frac{11}{14}\cdot r^2\\\\r^2=\frac{38.5\cdot14}{11}\\\\r^2=49\\\\r=7$

The diameter of the circle is twice the radius. Hence, diameter of the circle is given by

d = 2r

d = 2 × 7

d = 14 cm

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