Question

If area of rectangle is 1260 and perimenter 146 .what is its diagonal
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Answer 1

Answer:

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Step-by-step explanation:

ANSWER

Side of the rhombus

=4146=36.5cm

AO=21×(55)cm=27.5cm

OB=(AB)2−(AO)2=(36.5)2−(27.5)2=24cm

∴ BD=2×24cm=48cm

Hence Area =21×AC×BD=21×48×55sq.cm

=1320 sq.cm

Answer 2

Given:-

• Area of rectangle is 1260 cm².
• Perimeter of rectangle is 146 cm.

To Find:-

• What is its length of breadth ?

Solution:

Lets consider the length = " l ' and breadth = "b'

Now, we know

➹ Area of rectangle = Length × Breadth

➹ Perimeter = 2(Length + Breadth)

Perimeter = 2(l + b) = 146

⇒ l + b = 146/2

⇒ l + b = 73

⇒ l = 73 – b........eq(1)

Now,

⇒ Area = l × b = 1260

length taking from equation 1

⇒ (73 – b) × b = 1260

⇒ 73b – b² = 1260

⇒ 0 = b² – 73b + 1260

Now,

Applying middle term splitting method

⇒ b² – 73b + 1260

⇒ b² – 45b – 28b + 1260

⇒ b(b – 45) – 28(b – 45)

⇒ (b – 28) (b – 45)

⇒ b = 28 or b = 45

lets put value of b in equation (1).

• Length = 73 – b = 73 – 28 ↠ 45 cm
• Breadth ↠ 28 cm

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