Question

If area of Rectangle is 238 cm² and perimeter is 62 cm. Find the length and breadth​

Answer 1

$\huge\mathfrak \red{solution}$

$\huge{ \: \fbox{{given}}}$

✰ Area of Rectangle = 238 cm²

✰ Perimetre = 62 cm

$\huge{ \: \fbox{find}}$

✰ Length

✰ Breadth

_______________________________

$\small\mathfrak \red{formule \: \: }$

✰ Length = Area / Breadth

_______________________________

L× B = 238

2 ( L+B ) = 62

L = 238/B

2 (238/B+B ) = 62

238/B+B = 31

238 + B² = 31 B

B²- 31 B + 238 = 0

So ,it's an quadratic equation and W = (14 , 17)

Taking the lower amount as Width or Breadth and the higher amount as Length

L = 17

B = 14

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Rechecking

P = 2 (L+B)

P = 2(17+14)

P = 34+28

62 = 62 ✔︎

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Area = L×B

238 = 17×14

238 = 238 ✔︎

Answer 2

Answer:

✰ Area of Rectangle = 238 cm²

✰ Perimetre = 62 cm

\huge{ \: \fbox{find}}find

✰ Length

✰ Breadth

_______________________________

\small\mathfrak \red{formule \: \: }formule

✰ Length = Area / Breadth

_______________________________

L× B = 238

2 ( L+B ) = 62

L = 238/B

2 (238/B+B ) = 62

238/B+B = 31

238 + B² = 31 B

B²- 31 B + 238 = 0

So ,it's an quadratic equation and W = (14 , 17)

Taking the lower amount as Width or Breadth and the higher amount as Length

L = 17

B = 14