If area of rhombus is 128cm square and one of its diagonal is 16 cm . find the length of other two diagonals.
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Given: Area of Rhombus = 128 cm²
Diagonal of Rhombus = 16 Cm
Let the another Diagonal of Rhombus is (x) cm
↪We know that Formula of Rhombus :↩
↪Area of Rhombus = D1×D2 ÷ 2
↪128 = 16 × (x) ÷ 2
↪128×2 = 16x
↪256=16x
↪X=16
Hence, Required value of other diagonal is 16 cm
Diagonal of Rhombus = 16 Cm
Let the another Diagonal of Rhombus is (x) cm
↪We know that Formula of Rhombus :↩
↪Area of Rhombus = D1×D2 ÷ 2
↪128 = 16 × (x) ÷ 2
↪128×2 = 16x
↪256=16x
↪X=16
Hence, Required value of other diagonal is 16 cm
Anonymous:
:-)
256 ÷ 16 = 16
So, the right answer is 16
Nice...☺
hello
In which school do u read
sixteen(16)
What
Answer is 16
I will edit my answer.
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