Question

If area of rhombus is 96sq. cm and one of its diagonal is 16cm. find length of its side

Answer 1

Heya !!!!

Length of one diagonal = 16 cm


Let length of other diagonal be X cm.




Area of rhombus = 96 cm²





1/2 × ( Product of diagonals ) = 96


1/2 × ( 16 × X ) = 96

16X = 192


X = 192/16


X = 12 cm

Hence,

Length of other diagonal = X = 12 cm


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Answer 2

⇔⇔⇔⇔⇔ YOUR QUESTION :-
If area of rhombus is 96sq. cm and one of its diagonal is 16cm. find length of its side ?????????

⇔⇔⇔⇔⇔YOUR ANSWER ↓↓↓↓↓↓ :-

Given :- 
              Area of rhombus      = 96 sq . cm
              Length of  Diagonal = 16 cm.

To find :-
              Length of the Side of rhombus .

SOLUTION :-
               Let the other Diagonal be $D_{2}$.

 We Know that ,
                          Area of Rhombus = $\frac{1}{2} * d_{1} * d_{2}$
By putting Values in Formula ,
                           96 = $\frac{1}{2}* 16 * d_{2}$
                           $d_{2}$ = 12 cm.

Using PHYTAGORA THEORM,
$side^{2} = d1/2^{2} + d2/2^{2}$
$side^{2} = 36 + 64$
$side = \sqrt{100}$
side = 10 cm.

Hence Side = 10 cm .

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