if area of right angle traingle is equal to the area of square if heght of traingle is 25 unit then find the perimeter of square
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if b is the base of the Δ, then
area of Δ = b*25/2
sides-b, 25, √(b²+25²)
area of square=side²=b*25/2
side=5√(b/2)
perimeter=4*side=20√(b/2)
area of Δ = b*25/2
sides-b, 25, √(b²+25²)
area of square=side²=b*25/2
side=5√(b/2)
perimeter=4*side=20√(b/2)
dahnush:
hi
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