Question

If area of right angled triangle 216 m and base is 24m find the perimeter of triangle

Answer 1

Area of right Δ = 216m²

Base = 24m

1/2*b*h = 216

1/2*24*h = 216

h = 216*12

h = 18m

In right Δ ABC,

(AB)²+(BC)² = (AC)²                          (Pythagoras theorem)

(18)²+(24)² = (AC)²

AC = √(18)²+(24)²

AC = √324+576

AC = √900

AC = 30 m

AB = 18 m, BC = 24 m, AC = 30 m

Perimeter = AB+BC+CA = (18+24+30) m

= 72 m

Hence, the perimeter of right Δ ABC = 72 m