Question

if area of rombus is 100cm2 and one of its diagnol is twice of other them find the value of bigger diagonal​

Answer 1

Step-by-step explanation:

let first diagnol=x

second diagnol=2x

x×2x=200

then x^2=100

x=10

bigger diagnol=10×2=20

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Answer 2

$\small{\textsf{\textbf{\underline{\underline{The value of bigger diagonal is 20 cm. \::}}}}}$

Step-by-step explanation:

Given that:

• Area of a rhombus is 100 cm².
• One of its diagnol is twice of other.

To Find:

• The value of bigger diagonal.

Let us assume:

• Smaller diagonal of a rhombus be x.
• Bigger diagonal = 2x

Formula used:

Area of a rhombus = (P × Q)/2

Where,

• P = Bigger diagonal of a rhombus
• Q = Smaller diagonal of a rhombus

Finding the value of bigger diagonal:

According to the question.

⟶ (P × Q)/2 = 100

⟶ (2x × x)/2 = 100

⟶ 2x²/2 = 100

⟶ x² = 100

⟶ x = √100

⟶ x = 10

$\small{\textsf{\textbf{\underline{\underline{∴ The value of bigger diagonal = 2x = (2 × 10) = 20 cm\::}}}}}$