Question

if area of rombus is 100cm2 and one of its diagnol is twice of other them find the value of bigger diagonal​

Answer 1

Answer:

• The value of bigger diagonal is 20 cm.

Step-by-step explanation:

Given that:

• Area of a rhombus is 100 cm².
• One of its diagnol is twice of other.

To Find:

• The value of bigger diagonal.

Let us assume:

• Smaller diagonal of a rhombus be x.
• Bigger diagonal = 2x

Formula used:

• Area of a rhombus = (P × Q)/2

Where,

• P = Bigger diagonal of a rhombus
• Q = Smaller diagonal of a rhombus

Finding the value of bigger diagonal:

According to the question.

⟶ (P × Q)/2 = 100

⟶ (2x × x)/2 = 100

⟶ 2x²/2 = 100

⟶ x² = 100

⟶ x = √100

⟶ x = 10

∴ The value of bigger diagonal = 2x = (2 × 10) = 20 cm

Answer 2

Answer:

20cm

Step by step explanation:

Given,

Area of rhombus = 100cm^2 and one diagonal is twice the other.

Now,

Let one diagonal be Y and the other diagonal be 2Y

Area of rhombus = 1/2 x length of Diagonal 1 × length of diagonal 2

substituting the values in the above formula,

100 = 1/2 x Y x 2Y

100 = 1/2 x 2Y^2

100 = Y^2 (2 and 2 cancels out in the previous step)

root100 = Y

10cm = Y

Therefore the first diagonal will be = Y = 10cm

And second diagonal will be = 2Y = 2x10 = 20cm

So the length of bigger diagonal is 20cm.