if area of rombus is 100cm2 and one of its diagnol is twice of other them find the value of bigger diagonal?
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Step-by-step explanation:
Let, the value of small diagonal is=X
And bigger is=2X
According to the question,
Area=100cm2
=(2X*X) /2=100
=2X^2=2*100
=2X^2=200
=X^2=200/2
=X^2=100
=X=10cm
So,2X=2*10=20
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