if area of rombus is 100cm2 and one of its diagnol is twice of other them find the value of bigger diagonal
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Answer:
Area of a rhombus is 100 cm².
One of its diagnol is twice of other.
To Find:
The value of bigger diagonal.
Let us assume:
Smaller diagonal of a rhombus be x.
Bigger diagonal = 2x
Formula used:
Area of a rhombus = (P × Q)/2
Where,
P = Bigger diagonal of a rhombus
Answered by
1
Answer:
Area of Rhombus = 100cm^2
Let the smaller diagonal be x therfore bigger diagonal is 2x
By Formula,
ar(rhombus) = 1/2× d1×d2 ( d1 and d2 are
diagonals of rhombus)
:.100 = 1/2 × x × 2x
:. 100 = x× x
:. 100 = x^2
:.x = √100
:. x = 10cm
Therefore smaller diagonal is 10 cm and bigger diagonal is 2x=2(10) = 20 cm
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