Math, asked by vaishukp3589, 1 year ago

If area of rombus is 72 and perimeter is 32 fimd altitude

Answers

Answered by mrunalsonawane1331
2

length of side= 32/4=8cm

it's height =area /length of side

= 72/8=9cm Answer

hope it helps..


Answered by satuu43
0
(Given)

Area = 72 cm sq.

=>Perimeter of the Rhombus = 32 cm
4 × Side = 32
4s = 32
s = 32 / 4
s = 8

So, each side = 8 cm.

=> Area of the Rhombus = 72 cm sq.
Base × Height = 72
b × h = 72
8h = 72
h = 72 /8
h = 9


So, altitude of the Rhombus is 9 cm.

satuu43: If my answer helps you then PLEASE mark it as the Brainliest answer!
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