If area of similar triangles abc and def be 64 sq cm and 121 sq cm and ef = 15.4 then bc equals to
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Answered by
4
Area of ∆ ABC = 64 cm²
Area of ∆ DEF = 121 cm²
We know that :-
∆ ABC ∆ DEF
We also know :-
BC = 11.2 cm
Answered by
0
\frak {\underline{\orange{Answer}}}
Answer
Area of ∆ ABC = 64 cm²
Area of ∆ DEF = 121 cm²
We know that :-
∆ ABC \sim∼ ∆ DEF
We also know :-
\sf \frac{ar(ABC)}{ar(DEF)} = {(\frac{AB}{DE} )}^{2}= {(\frac{BC}{EF} )}^{2}={(\frac{AC}{DF} )}^{2}
ar(DEF)
ar(ABC)
=(
DE
AB
)
2
=(
EF
BC
)
2
=(
DF
AC
)
2
\sf \frac{64}{121} = { (\frac{(BC)}{(15.4)}) }^{2}
121
64
=(
(15.4)
(BC)
)
2
\sf \frac{BC}{15.4} = \sqrt{ \frac{64}{121} }
15.4
BC
=
121
64
\sf \frac{BC}{15.4} = \frac{8}{11}
15.4
BC
=
11
8
\sf BC = \frac{8}{11} \times 15.4BC=
11
8
×15.4
\boxed{\purple{\sf{ BC = 11.2}}}
BC=11.2
BC = 11.2 cm
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