Question

If area of similar triangles abc and def be 64 sq cm and 121 sq cm and ef = 15.4 cm then bc equals what?

Answer 1

Then area abc/area def=64/121

Area abc/area def=bc^2/ef^2

64/121=bc^2/ef^2

8/11=bc/15.4

Bc=11.2 cm

Answer 2

hey mate this is ur answer..