Question

if area of square is x²-10x+25 than finds its perimeter​

Answer 1

Answer:

x²-10x+25=0

x²-5x-5x+25=0

x(x-5) -5(x-5) =0

(x-5) (x-5) =0

(x-5) =0 or (x-5) =0

x-5=0

x=5

perimeter is 5