Question

If area of the rhombus is 24 cm square and one of its diagonal is 4 cm find the perimeter of the rhombus

Answer 1

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▪️Area of rhombus = 24 cm square

▪️One of its diagonal = 4 cm

▪️Let its other diagonal be X

▪️So , 1/2 * 4 * X = 24cm square

▪️x = 12 cm

▪️We know that the diagonals of a rhombus bisect each other at eight angle.

▪️Now from one of the right triangle within it we will calculate the side of the rhombus.

▪️The one of the side we get from above process = ( 36 + 4 ) ^ 1/ 2 = 40 ^ 1/2 = 2√ 10

▪️So, perimeter of the given rhombus

= 4 * 22√10

= 82√ 10

Hopes it help you✌️✌️

Answer 2

Answer:

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