Question

If area of total surface of a cube is 4 times more than that of another cube, then how many

times will be the volume of the first cube?

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Answer 1

Step-by-step explanation:

Let the length of each edge of a cube = x units. ,its total surface area = 6.x^2. units ^2.

Now the length of each edge is 2.x units., its total surface area = 6.(2x)^2 = 24.x^2.units ^2.

Increase in surface area = 24x^2 - 6x^2 = 18.x^2.units ^2. = 3× 6x^2.units ^2.

Total surface area of the new cube will increase the three times of the total surface

area of the original cube. Answer.

Answer 2

Answer :-

• Let side of first cube = a1
• side of second cube = a2 .

given that,

→ TSA of first cube = 4 times more more than that of second cube = (1 + 4) times of TSA of second cube

→ 6(a1)² = 5 * 6(a2)²

→ (a1)²/(a2²) = 30/6

→ (a1)²/(a2²) = 5/1

→ (a1/a2) = √5/1

then,

→ Volume of first cube / Volume of second cube = (a1)³ / (a2)³ = (√5)³ / 1 = 5√5 / 1

therefore, Volume of first cube is 5√5 times of the volume of the second cube .