if Area of triangle ABC =9cm^2, area of triangleDEF=64^2 , DE=5.6 the find AB.........triangle ABC similar to triangle DEF.....(given)
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Step-by-step explanation:
area of ABC = 9cm^2
area of DEF = 64cm^2
length of DE = 5.6cm
since, ∆ABC ~ ∆DEF
So, ratio of areas of ∆ABC&∆DEF = ratio of length of similar sides
=> ∆ABC/∆DEF = AB/DE = BC/EF = CA/FD
=> 9/64 = AB/5.6
=> AB = 9×5.6 / 64
=> AB = 50.4 /64 = 0.78cm
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