Question

if area of triangle abc is 4 units and co ordinates of abc are (x,3),(4,-4),(3,-5)​

Answer 1

Answer:

$area \: of \: triangle \: abc = 4 \: units \\ \red{\frac{1}{2}(x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2))=4} \\ \frac{1}{2} (x( - 4 + 5) + 4( - 5 - 3) + 3(3 + 4)) = 4 \\ x - 32 + 21 = 4 \\ x - 11 = 4 \\ \boxed{x = 15}$