Math, asked by vivekkumarraj7126, 1 year ago

If area of triangle abc is 64 sq cms amd of triangle def is 121 sq cms and ef =15.4 then bc =

Answers

Answered by Anonymous
100

\frak {\underline{\orange{Answer}}}

Area of ∆ ABC = 64 cm²

Area of ∆ DEF = 121 cm²

We know that :-

∆ ABC \sim ∆ DEF

We also know :-

 \sf \frac{ar(ABC)}{ar(DEF)}  =    {(\frac{AB}{DE} )}^{2}= {(\frac{BC}{EF} )}^{2}={(\frac{AC}{DF} )}^{2}

 \sf \frac{64}{121}  =  { (\frac{(BC)}{(15.4)}) }^{2}

 \sf \frac{BC}{15.4}  =  \sqrt{ \frac{64}{121} }

 \sf \frac{BC}{15.4}  =  \frac{8}{11}

 \sf BC =  \frac{8}{11}  \times 15.4

 \boxed{\purple{\sf{ BC = 11.2}}}

BC = 11.2 cm

Similar questions