If area of triangle be 35 square unit and its vertices are (2,–6), (5,4) and (k, 4) then the value of k is
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Answer:k=(-2)
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area of triangle=1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]
35=1/2[2(4-4)+5(4+6)+k(-6-4)]
70=[2(0)+5(10)+k(-10)]
70=(0+50-10k)
70=50-10k
20=-10k
-2=k
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