if area of triangle formed by points are (a,0) (1,1) (0,2) is 4 sq.units find a
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Area = 1/2 | x1(y2-y3) + x2(y3-y1) +x3(y1-y2) |
4 = 1/2 | a(-1) + 1(2) + 0(0-1) |
8 = |-a+2|
2 - a = 8 or 2-a = -8
a = -6 or a = 10
4 = 1/2 | a(-1) + 1(2) + 0(0-1) |
8 = |-a+2|
2 - a = 8 or 2-a = -8
a = -6 or a = 10
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