Question

if area of triangle formed by the vertices A(-1,2) B(k,-2)and C(7,4)taken in order is 22sq units find the value of k​

Answer 1

Step-by-step-explaination:

Given

A(-1,2) B(k,-2) C(7,4)

(X1,y1) (X2,y2) (x3,y3)

Area of triangle=1/2|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|

=1/2|-1(-2-4)+k(4-2)+7(2-(-2)|=22

=1/2|-1(-6)+k(2)+7(2+2)|=22

=1/2|-1(-6)+k(2)+7(4)|=22

=1/2|6+2k+28|=22

=1|34+2k|=22×2

=34+2k=44

=2k=44-34

=2k=10

=k=10/2

=k=5

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Answer 2

Answer:

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