if area of triangle is 13 square units find the area of triangle whose vertices are mid points of the sides of previous triangle
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Step-by-step explanation:
since D,E and F are the midpoints of AB, BC and CA of triangle respectively
coordinate of D=(1,0)
coordinate of E=(1,2)
coordinate of F=(0,1)
∴ar(△DEF)=
1/2 [1(2−1)+1(1−0)+0(0−2)]=1sq.unit
andar(△ABC)=
1/2 [0(1−3)+2(3+1)+0(−1−1)]=4sq.unit
ar(△ABC)
ar(△DEF)
=
4
1
⇒ar(△DEF):ar(△ABC)=1:4
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Answer:
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