Question

If area of triangle is 48cm square and altitude is 8cm its base will be

Answer 1

It is given that,

In a triangle ( right - angled ),

• Area = 48 cm
• Altitude = 8 cm

We know that,

AREA OF THE TRIANGLE

= 1/2 × Base × Height

Substitute the known values in the above formula.

we get,

48 = 1/2 × b × 8

➡ 48 = 4b

➡ b = 48/4

•°• b = 12

Hence,

Base of the given triangle is 12 cm.

$\rule{200}2$

Answer 2

Answer:

$\huge\bold\red{ solution }$

given;

area of triangle = $48cm ^{2}$

altitude = 8cm

now ;

area of ∆ = $\frac{1}{2} \times base \times height$

$48 = \frac{1}{2} \times b \times 8 \\ \\ 48 = 4b \\ \\ b = \frac{48}{4} \\ b = 12 \\ \\ hence \: base \: = 12cm$