Question

If area of triangle is 75 square meters and two of its sides are 20 and 15 square meters then included angle is​

Answer 1

Answer:

25 meter

Step-by-step explanation:

√20^2+15^2 applying Pythagoras theorem

=√400+225

=√625=25meter

Answer 2

Given,

A triangle with area, $A=75m^{2}$

And the sides,

$a=20m\\b=15m$

To find,

Angle between the sides $a$ and $b$.

Solution,

We know that,

Area of triangle when two of the sides and angle between them is given is given by,

$Area=\frac{1}{2} absin\beta$

where $\beta$ is the angle between the sides $a$ and $b$.

By using this formula, we can say that,

$A=\frac{1}{2}absin\beta$

⇒$75m^{2}=\frac{1}{2}(20)(15)sin\beta$

⇒$sin\beta =75(\frac{1}{(20)(15)} )(2)$

⇒$sin\beta =\frac{75}{150}$

⇒$sin\beta =\frac{1}{2}$

⇒$\beta =30$°

Therefore, the angle between the given sides of the given triangle is 30°.