Question

If argument of the complex number z = cosθ + isinθ is θ, then argument of 1 + cosθ + isinθ is,​

Answer 1

Step-by-step explanation:

Answer

We have

z

1

=

cosθ+isinθ

1

=cosθ−isinθ

∴z

n

=(cosθ+isinθ)

n

=cosnθ+isinnθ

and

z

n

1

=(cosθ−isinθ)

n

=cosnθ−isinnθ

Hence z

n

+

z

n

1

=2cosnθ and z

n

−

z

n

1

=2isinnθ