Question

if arithmetic mean of a,a+3,a-6,a+9anda+12 is 10 ,then a is equal to

Answer 1

Step-by-step explanation:

AM=a+a+3+a-6+a+9+12/5=10

a+a+a+a+3-6+9+12/5=10

4a+(-3)+21/5=10

4a+18/5=10

4a+18=10*5

4a+18=50

4a=50-18

4a=32

a=32/4=8

Answer 2

a+(a+3)+(a-6)+(a+9) +(a+12) ÷5=10

(a+a+3+a-6+a+9+a+12)÷5=10

(5a+18) ÷5=10

5a+18=10×5

5a=50-18

5a=32

a=6.4 answer