If asinθ=1, btanθ=1; then prove that a^2-b^2=1
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asin@=1,
then
a=1/sin@,
[email protected](1),
btan@=1,
then
b=1/tan@,
[email protected](2),
therefore
a²-b²=cosec²@-cot²@,
a²-b²=1,
since
cosec²@-cot²@=1
then
a=1/sin@,
[email protected](1),
btan@=1,
then
b=1/tan@,
[email protected](2),
therefore
a²-b²=cosec²@-cot²@,
a²-b²=1,
since
cosec²@-cot²@=1
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