If asinθ=1, btanθ=1; what is the relation between a and b?
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asinx=1 =>a=1/sinx or a^2=1/sin^2x (eq-1)
btanx=1 =>b=1/tanx or b^2=1/tan^2x ( eq-2)
eq1-eq2
a^2-b^2=1/sin^2x -1/tan^2x
=(1-cos^2x)/sin^2x (by using property sin^2x+cos^2x=1)
=sin^2x/sin^2x
=1
vicky123465:
this is not the right answer
what,s the answer then
a^2-b^2=2
sorry
this is not the right answer
a^2-b^2=1
this is the right answer
ok
wait i will edit my answer
done
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