Question

If asinθ=1, btanθ=1; what is the relation between a and b?

Answer 1

asinx=1 =>a=1/sinx or a^2=1/sin^2x (eq-1)

btanx=1 =>b=1/tanx or b^2=1/tan^2x ( eq-2)

eq1-eq2

a^2-b^2=1/sin^2x -1/tan^2x

=(1-cos^2x)/sin^2x (by using property sin^2x+cos^2x=1)

=sin^2x/sin^2x

=1