Question

If asin² (x) + bcos² (x) = c, bsin² (y) + acos² (y) = d and atan (x) = btan (y). Then prove that : a²/b² = (d - a) (c - a)/(b - c) (b - d).



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Answer 1

correct answer is that a²/b² is equal to ( a - d ) ( c - a ) / ( b - c ) ( d - b )

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