Question

If @ and # are zeros of p(x) =2x^2 - x - 6, then value of @^ -1 + #^ -1 = __ .

Answer 1

Answer :

The given polynomial is

p(x) = 2x² - x - 6

If @ and # are to zeroes of p(x), then

@ + # = - (- 1)/2 = 1/2 ...(i)

and

@ # = - 6/2 = - 3 ...(ii)

Now,

@^(- 1) + #^(- 1)

= 1/@ + 1/#

= (# + @)/(@ #)

= (1/2)/(- 3), by (i) and (ii)

= - 1/6

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