if at certain temperature the ionic product of pure water is 10^-12 then pH of pure water at that temperature is
a)6
b)7
c)12
d)14
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6
This is the ionic product of water
Which contain the Ionic concentration of both H+and OH-
Therefore the concentration of H+will be half of ionic product o water i.e 10^-6
And as we know
PH =-log[H+]
=-log[10^-6]
PH = 6
This is the ionic product of water
Which contain the Ionic concentration of both H+and OH-
Therefore the concentration of H+will be half of ionic product o water i.e 10^-6
And as we know
PH =-log[H+]
=-log[10^-6]
PH = 6
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