Question

If at depth (h) acceleration due to gravity is decreased by 25% as compared to the
surface of earth then at the height (h) it will decrease by (in comparison with
surface of earth)​

Answer 1

Answer:

(a)At earth's surface g=

R

2

GM

..(1)

At x,g

′

=0.25g=

4

g

=

x

2

GM

..(2)

(1) ÷ (2)

4=

R

@

x

2

x=2R

x=2×6400=12800km

Height from earth's surface is (x−R)=6400km

(b)At surface, g=

R

2

GM

=

R

2

G

×ρ×

3

4

πR

3

=

3

4

ρGπR

At depth h,

g

g

′

=

R

R−h

=1−

R

h

g

′

=g(1−

R

h

)

% decrease,

g

g−g

′

=

g(1−

R

h

)

g−

R

h

=

R−h

h

%decrease=

R−h

100h

Answer 2

Answer:

hope it helps u friend:)