Question

If at the moment t=0 the separation between the cars is 90m and the length of each car is 5 m the moment of time at which they completely cross each other is?

Options
1s
4s
22s
3.6s

Answer 1

question is incomplete. A complete question is ----> A car P moves due east with a speed 10 m/s and another car Q moves due west with a speed 15 m/s. If at the moment t =0; yhe seperation between the cars is 90 m and length of each car is 5 m, the moment of time at which they completely cross each other is

answer :

explanation : speed of car P,$v_P$ = 10m/s towards East.

speed of car Q , $v_Q$ = 15m/s towards west.

initial seperation between cars , S = 90m

length of each car is 5m.

so, time taken to cross each other , t = (seperation between them + length of car P + length of car Q)/(speed of car P + speed of car Q)

= (90m + 5m + 5m)/(10m/s + 15m/s)

= 100m/25m/s

= 4s

Answer 2

Answer: 4 sec

PLZ MARK IT AS THE BRAINLIEST!!!

Explanation: After reading the complete question , following is its solution :-

Speed of car P = 10m/s. Length of car P = 5m

Speed of car Q = 15m/s. Length of car Q= 5m

Seperation b/w both the cars = 90 m

Time taken to cross each other =( seperation b/w cars + length of both cars) ÷ (speed of cars)

= (90+5+5) ÷ (10+15)

=100÷25

= 4 seconds

HOPE IT HELPS!