if atmospheric pressure is 1.01×10^5 pascal then how much force does the air in a room exert on the inside of a window pane which is 50 cm × 100 cm ? Please help!
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atmospheric pressure = 1.01 ×10^5 pa
area of window pane = 50cm* 100cm = 5000cm^2
and we can convert it this quantity in m = 5000/100*100 = 0.5m²
now buddy i will use the formula force = pressure * area
which means :-
force = 1.01*10^5pa ×0.5m² which means
force = 5.05 ×10^4 N
have any doubts buddy ask in comment section !
Hope this helps you !
cheers !
area of window pane = 50cm* 100cm = 5000cm^2
and we can convert it this quantity in m = 5000/100*100 = 0.5m²
now buddy i will use the formula force = pressure * area
which means :-
force = 1.01*10^5pa ×0.5m² which means
force = 5.05 ×10^4 N
have any doubts buddy ask in comment section !
Hope this helps you !
cheers !
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