Question

If atmospheric pressure on a certain day is 749 mmHg, what is the partial pressure of nitrogen, given that nitrogen is about 78% of the atmosphere?

Answer 1

Answer:

The partial pressure of the nitrogen gas is 584.22 mmHg.

Explanation:

Given that percentage of the nitrogen in the atmosphere is 78 %.

Mole fraction of nitrogen in the atmosphere =  0.78

Total pressure of the air = 749 mmHg

According to Raoults law:

$p_{N_2}=\chi_{N_2}\times p_{total}$

$p_{N_2}=0.78\times 749 mmHg =584.22 mmHg$

The partial pressure of the nitrogen gas is 584.22 mmHg.