Question

If atomicity of Phosphorus is 4 & its atomic mass is 31g, the no. of moles of Phosphorus molecules & the no. of atoms of Phosphorus present in 0.124g of Phosphorus molecule are respectively :


A) 0.001 & (1/1000) X Avogadro No.
B) 0.01 & (1/100) X Avogadro No.
C) 0.1 & (1/10) X Avogadro No.
D) None of the above

Answer 1

Answer:

the correct answer is option A) 0.001 and (1/1000)× Avogadro Number

Or, D) None of this.

Explanation:

The molar mass of phosphorus= atomicity×atomic mass= 4×31 g= 124g

→Mass of 1 mole of phosphorus molecule is 124g.

→0.124 g of phosphorus contain 1/1000 mole of phosphorus molecule.

→0.124 g of phosphorus contain 1/1000×Avogadro No. of phosphorus molecule.

→0.124 g of phosphorus contain 4×1/1000×Avogadro No. of phosphorus atoms.

Make sure that the question is correct. If the question is correct then the answer will be option D .

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