Question

If Atul is 20% taller than Ajay,by what percentage is Ajay shorter than Atul?
pplz answer step by step

Answer 1

Let Ajay be x units tall

Find the height of Atui in term of x:

20% taller = 0.2x

height = x + 0.2x = 1.2x

Atul is 1.2x units tall

Find the difference in height:

1.2x - x = 0.2x

Find the percentage difference in their height:

0.2x/1.2x x 100 = 16.67%

Answer: Ajay is 16.67% shorter than Atul.

Answer 2

Answer:

16.67%

Step-by-step explanation:

Let's assume Ajay's height as x or for easy understanding let's assume Ajay's height to be 100 cm. As mentioned, Atul's height is more than Ajay's height by 20% so we will calculate what is 20% of 100 and add it to Ajaysy height. So 20% of 100 is 20 . So Atul's height is (100+20)cm=120 cm.

Now by how much Atulsl's height is more than Ajay's? It is (120-100)cm=20cm. Now we have to find by how much Ajay's height is less than Atul's. So it is (20÷120×100)cm=approx 16.67%.( here remember that you have to divide the difference in heights by the height of Atul because we are finding the percent of Ajay's height with respect to Atul i.e. by how much Ajay's height is less than Atul's ).

Now let's come to the answer of your question. Assume Ajay's height to be x. By the same method you can find it and the answer will come to be 16.67%.

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