If average of age of 5 members of family is 25.The youngest of family is 10 years old.Find the average of age of family before the youngest has born
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The total sum of ages of family be x
Then
Average=total sum of ages/no. of family members
25=x/5
x=25 x 5
x=125
The total sum of ages of family members is 125.
Age of the youngest member is 10 years.
Sum of the ages of family members before youngest has born=Total sum - age of youngest
sum =125 -10
=115
The total sum of members of family except the youngest is 115 years.
Total number of family members =4
Average =115/4
=28.75 years
Therefore the average of the age of family members except the youngest member is
28.75years.
Make the answer as brainlist answer
Then
Average=total sum of ages/no. of family members
25=x/5
x=25 x 5
x=125
The total sum of ages of family members is 125.
Age of the youngest member is 10 years.
Sum of the ages of family members before youngest has born=Total sum - age of youngest
sum =125 -10
=115
The total sum of members of family except the youngest is 115 years.
Total number of family members =4
Average =115/4
=28.75 years
Therefore the average of the age of family members except the youngest member is
28.75years.
Make the answer as brainlist answer
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