if average of two numbers x and 1/x is 4 what will be the average of x^3 amd 1/x^3
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Average of x and 1/x = 4
So,
(x+1/x)/2 = 4
Or, x+1/x = 8
Now, average of x^3 and 1/x^3 = (x^3+1/x^3)/2
= {(x+1/x)^3 - 3(x+1/x)}/2 [ by formula]
= {(8^3) - (3×8)}/2 [ since x+1/x = 8 ]
= (512 - 24)/2
= 488/2
= 244 (ANS)
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