If ax-1 = by+1 then find the value of (x, y) ?
Answers
Answered by
0
Answer:
We have,
ax−1=bc
aax=abc
ax=abc
a=(abc)1/x …(1)
Similarly,
b=(abc)1/y …(2)
c=(abc)1/z …(3)
Multiply (1),(2),(3)
abc=(abc)1/x.(abc)1/y.(abc)1/z
abc=(abc)1/x+1/y+1/z
∴ x1+y1+z1=1
xyzxy+yz+zx=1
xy+yz+zx=xyz
xy+yz+zx−xyz=0
Hence, this is the answer.
Similar questions