Question

if ax^2+bx+c
then 1/alpha+1/Beta=?​

Answer 1

Answer:

$\large{ \bold{ - \frac{b}{c} }}$

Step-by-step explanation:

$a {x}^{2} + bx + c = 0 \\ \\ \: \alpha + \beta = - \frac{b}{a} \\ \\ \alpha \beta = \frac{c}{a} \\ \\ now \\ \\ \frac{1}{ \alpha } + \frac{1}{ \beta } \\ \\ = \frac{ \alpha + \beta }{ \alpha \beta } \\ \\ = \frac{ - \frac{b}{a} }{ \frac{c}{a} } \\ \\ = - \frac{b}{c}$

HOPE IT HELPS