If ax^2+by^2+cz^2+2fyz+2gzx+2hxy=0 represents
the equation of pair of planes then show that
abc+2fgh-af^2-bg^2-ch^2=0 and f^2>bc,g^2>ac,h^2>ab
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Equation of bisectors of angle between the pair of straight line ax2+2hxy+by2=0 is given by a−bx2−y2=hxy
⇒hx2−(a−b)xy−hy2=0
Here coefficient of x2+ coefficient of y2=h+(−h)=0
∴ above equation represent the pair of ⊥er lines.
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