Question

if ( ax^3+2)^2=a^2x^6+x^3+4, then find a.​

Answer 1

Answer:

Step-by-step explanation:

( ax^3+2)^2=a^2x^6+x^3+4

a^2x^6+4+4ax^3=a^2x^6+x^3+4

4ax^3=x^3

4ax^3-x^3=0

x^3(4a-1)=0

So either x=0 or 4a-1=0

or 4a=1

a=1/4