if ax^3-3x^2-11x+20is a multiple of x+3 find value of a
Answers
Answered by
3
Answer:
a = 1
Step-by-step explanation:
x + 3) ax³ - 3x² - 11x + 20 ( x²
x³ + 3x²
- - ( symbols has changed + has - and - has + we can cancel
x cube terms )
the coefficient of x cube is 1
Answered by
30
Answer:
Answer is 26/27
Step-by-step explanation:
First we have to find out the zero of x+3 which is (-3).
Now pot -3 in p(x) as p(-3).
A/Q=P(x)=ax^3-3x^2-11x+20=0
=P(-3)=a(-3)^3 - 3(-3)^3 - 11(-3) + 20=0
=-27a-27+33+20=0
=-27a+6+20=0
=-27a+26=0
=-27a=0-26
=-27a=-26
=a=-26/-27
=a=26/27
Thank you
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