Question

if ax^3-3x^2-11x+20is a multiple of x+3 find value of a

Answer 1

Answer:

a = 1

Step-by-step explanation:

x + 3) ax³ - 3x² - 11x + 20 ( x²

         x³  + 3x²

        -       -   ( symbols has changed + has - and - has + we can cancel          

                                       x cube terms )

the coefficient of x cube is 1

Answer 2

Answer:

Answer is 26/27

Step-by-step explanation:

First we have to find out the zero of x+3 which is (-3).

Now pot -3 in p(x) as p(-3).

A/Q=P(x)=ax^3-3x^2-11x+20=0

=P(-3)=a(-3)^3 - 3(-3)^3 - 11(-3) + 20=0

=-27a-27+33+20=0

=-27a+6+20=0

=-27a+26=0

=-27a=0-26

=-27a=-26

=a=-26/-27

=a=26/27

Thank you